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16y^2-44y+24=0
a = 16; b = -44; c = +24;
Δ = b2-4ac
Δ = -442-4·16·24
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{400}=20$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-44)-20}{2*16}=\frac{24}{32} =3/4 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-44)+20}{2*16}=\frac{64}{32} =2 $
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